1.

For a first order reaction with half-life of 150 seconds, the time taken for the, concentration of the reactant to fall from M/10 to M/100 will be approximately

Answer»

1500 s
500 s
900 s
600 s

Solution :`k = 0.693/(t_(1//2))= 0.693/150 s^(-1)= 2.303/t log. (1//10)/(1//100)`
`or t = (2.303xx 150)/(0.693) log 10 - 498 -=500S`


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