For a fixes amount of real gas when a graph of z v//s was plotted than at very high pressure slope was observed to be 0.01 atm^(-1). At the same temperature if a graph is plotted b//w pv v//s P then for 2 moles of the gas 'Y' intercept is found to be 40 atm-litre. calculate excluded volume in litres for 20 moles of the real gas.

For a fixes amount of real gas when a graph of z v//s was plotted than

1.	For a fixes amount of real gas when a graph of z v//s was plotted than at very high pressure slope was observed to be 0.01 atm^(-1). At the same temperature if a graph is plotted b//w pv v//s P then for 2 moles of the gas 'Y' intercept is found to be 40 atm-litre. calculate excluded volume in litres for 20 moles of the real gas.
Answer» Solution :`:.` very high pressure `:.` NEGLECT (a) `:. Z = 1+(Pb)/(RT) ..(1)` comparing above equation with `y = mx +c` `:. M = (b)/(RT)` `rArr (b)/(RT) = 0.01` (GIVEN `m = 0.01)` `b = 0.01 RT ..(2)` `Z = ((PV)_(real))/((PV)_("ideal"))` ltbr. `Z = ((PV)_(real))/(nRT)` (given for `N = 2, PV = 40)` `Z = (40)/(2RT)` `Z (20)/(RT) ...(3)` as, `Z = 1+(Pb)/(RT)` from equation (3) `(20)/(RT) = 1+(Pb)/(RT) ..(4)` `10 = RT +Pb` `Pb = 20 - RT ...(5)` `(PV)_(real) = 40= ZnRT = (1+(Pb)/(2RT)) 2RT` `rArr 40 = (1+(20-RT)/(2RT)) 2RT` `40 = 2RT +20 - RT` `20 = RT...(6)` From (2) & (4) `b = 0.01 xx 20` `b = 0.2` excluded volume for 20 moles `nb = 20 xx 0.2` `nb = 4`