For `A(g) hArr 2B(g)`, equilibrium constant at total equilibrium press

1.	For `A(g) hArr 2B(g)`, equilibrium constant at total equilibrium pressure `p_(1)` is `K_(p1)& ` for `C(g)hArrD(g)+E(g)`. equilibrium constant at total equilibrium pressure `p_(2)` is `K_(p2)`. If degree of dissciation of `A & C` are same, then the ratio `K_(p1) //K_(p2)` , if `2p_(1)=p_(2)`, is `:`A. 2B. `1//8`C. `1//2`D. 8
Answer» Correct Answer - 1 `K_(p1)=(4alpha.^(2)P_(1))/(1-alpha^(2)),K_(p^(2))=(alpha^(2)P_(2))/(1-alpha^(2))rArr" "(K_(p_(1)))/(K_(p_(2)))=(4P_(1))/(P_(2))=4xx(1)/(2)=2`

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