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For a gaseous reaction, following data is given: `ArarrB, k_(1)= 10^(15)e-^(2000//T)``C rarrD, k_(2) = 10^(14)e^(-1000//T)` The temperature at which `k_(1) = k_(2)` isA. 1000KB. 2000 KC. `868.82 K`D. `443.2 K` |
Answer» When `k_(1)=k_(2)` `10^(15)e^(-2000//T)=10^(14)e^(-1000//T)` `10= e^(1000//T)` `2.303 log 10 =(1000)/(T)` |
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