1.

For a given exothermic reaction , K_(p) and k'_(p) are the equilibrium constants at temperatures T_(1) and T_(2) respectively. Assuming that heat of reaction is constant in temperaturerange between T_(1) and T_(2) , it is readily observed that

Answer»

`K_(p)=K'_(p)`
`K_(p)=(1)/(K'_(p))`
`K_(p)gtK'_(p)`
`K_(p)LTK'_(p)`

Solution :Assuming `T_(2)gtT_(1).`


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