1.

For a given mass of a gas , if pressure is reduced to half and its temperature is doubled, then volume V will become :

Answer»

4V
`2V^(2)`
`V//4`
8V

Solution :`p_(1) = p , p_(2) = p //2, T_(1) = T, T_(2) = 2T`,
`V _(1) = V, V_(2) = ? `
`( p_(1) V_(1))/( T_(1)) = ( p_(2)V_(2))/(T_(2))`
or `V_(2) = ( p _(1) V_(1) T_(2))/(p_(2) T_(1))`
`= ( p XX V xx 2T)/( p //2 xx T ) = 4V`


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