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For a given slit, ratio of diffraction angle of fringes of first maxima and first minima is...... |
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Answer» `(1)/(2)` `d sin theta_(N)=(2m+1)(lambda)/(2)` `sin theta_(1)=(3lambda)/(2D) "" [ :. m=1]` Condition for `m^(th)` order minimum `d sin theta_(m)=(lambda)/(d)` `(sin theta_(1))/(sin theta_(1))=(3lambda)/(2d)xx(d)/(lambda)=(3)/(2)` `:. (theta_(1))/(theta_(2))=(3)/(2)` |
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