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For a glass prism (mu = sqrt(3)) , the angle of minimum deviation is equal to the angle of the prism . Find the angle of the prism . |
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Answer» SOLUTION :REFRACTIVE INDEX of material of prism. `mu=(SIN""((A+D_m)/(2)))/(sin(A/2))` but `D_m = A` `thereforemu= sin A /("sin"A/2)` `= (2 sin""A/2 cos"" A/2)/(sin ""A/2) [ because sin theta = 2 sin"" theta/2cos ""theta/2]` `thereforesqrt(3) = 2 cos""A/2` `therefore cos""A/2 = sqrt(3)/(2)` `therefore A/2 = 30^@` `thereforeA = 60^@` |
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