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For a glass prism (n=sqrt(3)) the angle of minimum deviation is equal to the angle of the prism. Find the angle of prism. |
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Answer» Solution :Here, `D_(m) =A` and `n= sqrt(3)` `therefore n= sqrt(3) =(SIN(A+D_(m))/2)/(sin(A/2)) =(sin(A+A)/2)/(sin(A/2)) =(sinA)/(sinA/2) = (2 sin A/2 cos A/2)/(sin A/2) = 2 cos A/2` `therefore cos A/2 = sqrt(3)/2` or `A/2 = cos^(-1)(sqrt(3)/2) = 30^(@) rArr A= 60^(@)` |
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