InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
For a particle executing SHM, x = displacement from mean position, v = velocity and a = acceleration at any instant, thenA. `v - x` graph is a circleB. `v - x` graph is an ellipseC. `a - x` graph is a straight lineD. `a - x` graph is a circle |
|
Answer» Correct Answer - B::C `v = omega sqrt (A^(2) - x^(2))` `:. (v^(2))/(omega^(2)) + (x^(2))/((1)^(2)) = A^(2)` i.e. `v - x` graph is an ellipse. `a = - omega^(2)x` i.e. `a - x` graph is a straight line passing through origin with negative slope. |
|