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For a party 7 guests are invited by a husband and his wife. They sit in a row for dinner. The probability that the husband and his wife sit together, isA. `(2)/(7)`B. `(2)/(9)`C. `(1)/(9)`D. `(4)/(9)` |
Answer» Correct Answer - B The total number of ways in which 7 guests and the couple can sit in a row is 9!. Number of ways in which the husband and his wife sit together is `2!xx8!` `therefore` Required probability `=(2!xx8!)/(9!)=(2)/(9)` |
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