1.

For a person near point of vision is 100 cm. Then the power of lens he must wear so as have normal vision, should be

Answer»

<P> `+ 1D`
`- 1D`
`+ 3D`
`- 3D`

Solution :`f=(yD)/(y-D)=(100xx25)/(100-25)=(100)/(3)CM=(1)/(3)cm,p=(1)/(f)=+3D`


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