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For a photosensitive surface , work function is 3.3 xx 10^(-19) J. Taking plank's constant to be 6.6 xx 10^(-34) Js. Find threshold frequency. |
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Answer» SOLUTION :Here `W_0 = 3.3 xx 10 ^-19 J` `H = 6.6 xx 10^-34 JS` Threshold frequency `v_0 = W_0/h = (3.3 xx 10^-19)/(6.6 xx 10 ^-34) = 5 xx 10^14 Hz` |
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