1.

For a planet having mass equal to mass of the earth but radius is one fourth of radius of the earth. Then escape velocity for this planet will be

Answer»

`11.2" KM"//s`
`22.4" km"//s`
`5.6" km"//s`
`44.8" km"//s`

SOLUTION :`v_(E )=sqrt(2gR)=sqrt((2GM)/(R ))`
If R is `1//4"TH"` of radius of earth then
`v._(e )=2v_(e-"earth")=2xx11.2" km"//s =22.4" km//s`.


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