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For a planet having mass equal to mass of the earth but radius is one fourth of radius of the earth. Then escape velocity for this planet will be |
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Answer» `11.2" KM"//s` If R is `1//4"TH"` of radius of earth then `v._(e )=2v_(e-"earth")=2xx11.2" km"//s =22.4" km//s`. |
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