1.

For a point on the axis of the electric dipole theta = 0 and theta = pi = .. .. .. .. . , .........

Answer»

`-(KP)/(r^(2)),+(kP)/(r^(2))`
`+(kP)/(r^(2)),-(kP)/(r^(2))`
0,0
`+(kP)/(r),-(kP)/(r)`

Solution :For a point on DIPOLE AXIS `theta = 0^(@)` and `theta = pi`
`:. V =pm = (kP)/(r^(2))`


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