1.

For a primitive cubic crystal witha = 3 xx 10^(3)m,what is the smallest diffraction angle theta, for (1 1 0) plane for lambda = 1.50 xx 10^(-10) m?

Answer»

SOLUTION :We have,
`nlambda = 2dsin theta`
and `d = a/SQRT(H^(2) + k^(2) + l^(2))`
`therefore n lambda = (2a)/sqrt(h^(2) +k^(2) + l^(2)) sin theta`
For first-degree reflection, n=1
`1 xx 1.50 xx 10^(-10) = (2 xx 3 xx 10^(10))/sqrt(1^(2) + 1^(2) +0^(2)) sin theta`
`sin theta = (sqrt(2) xx 1.50 xx 10^(-10))/(6 xx 10^(10))`
`therefore theta = 20.70^(@)`.


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