1.

For a prism of refractive index 1.732, the angle of minimum deviation is equal to the angle of prism. Then the angle of the prism is

Answer»

`60^@`
`70^@`
`50^@`
none of these

Solution :`n=(sin((A+delta_m)/(2)))/(sin""A/2)=(sin(2A)/(2))/(sin""A/2)=(SINA)/(sin""A/2)`
`therefore 1.732=(2sinA//2cosA//2)/(sinA//2)`
`therefore 0.866=cos""A/2`
`therefore 30^@=A/2`
`therefore A=60^@`


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