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For a prism of refractive index `1.732`, the angle of minimum deviation is equal to the angle of the prism. The angle of the prism isA. `80^(@)`B. `70^(@)`C. `60^(@)`D. `50^(@)` |
Answer» Correct Answer - C `mu=(sin .(A+delta_(m))/(2))/(sin .(A)/(2))=(sin.(A+A)/(2))/(sin.(A)/(2))=(sinA)/(sin.(A)/(2))` `=(2sin.(A)/(2)cos .(A)/(2))/(sin.(A)/(2))=2 cos.(A)/(2)` So,`sqrt(3)=2 cos .(A)/(2)=(sqrt(3))/(2)=cos .(A)/(2)impliesA=60^(@)` |
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