1.

For a pure liquid (Specific gravity 2) having molar mass 50gm/mol. Ratio of molarity to molality is:

Answer»

20kg/LITRE
`(1)/(2)kg//litre`
200kg/litre
2000 kg/ `m^(3)`

Solution :For pure LIQ. TAKE 1 litre volume
`d=(2gm)/(ml)=("Mass of liquid")/(1000ml)rArr` Mass of liquid =200gm=2KG
`(M)/(m)=(n_("liq"))/(V("lit"))xx("Mass of solvent"(kg))/(n_(("liq")))=(2)/(1)kg//litre`
`=(2kg)/(10^(-3)m^(3))=2000kg//m^(2)`


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