1.

For a radioactive decay the value ofk = 2.7xx10^(-3)s^(-1) and initial concentration is 160 moles /L. After 100s the concentration of radioactive elementis :

Answer»

76 mol /L
122 mol /L
50 mol /L
80 mol /L

Solution :(B) `K = (2.303)/(t) "log" ([A]_(0))/([A])`
`2.7xx10^(-3) = (2.303)/(100) "log" (160)/([A])`
log` (160)/([A]) = 0.1172 `
`(160)/([A])` = 1.310
`:. [A] = (160)/(1.310)= 122 .13~~ 122 ` mol /L


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