1.

For a reaction A+2BrarrC, the amount of C formed by starting the reaction with 5 moles of A and 8 moles of B is

Answer»

5 moles
8 moles
16 moles
4 moles

Solution :`A+2BrarrC`
1 mole of A reacts with 2 moles of B
`therefore"5 moles of A will REACT with 10 moles of B."`
But we have only 8 moles of B.
HENCE, B is the limiting reactant
2 moles of B form 1 mole of C
`therefore"8 mole of B will form C = 4 moles."`


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