1.

For a reaction : A+B rarr Products the rate of the reaction of various concentrations are given below :{:("Expt No.",[A], [B]," ""Rate (mol dm"^(-3)s^(-1)),(1,0.2,0.2,""2),(2,0.2,0.4,""4),(3,0.6,0.4,""36):} The rate law for the above reaction is :

Answer»

`r= k[A]^(2)[B]`
`r = k[A][B]^(2)`
`r = k[A]^(3)[B]`
`r = k[A]^(2)[B]^(2)`

Solution :(A) When [B] is doubled and [A] is CONSTANT then the rate of reaction also doubles . Therefore order with respect to [B] =1 When [B] is constant and [A] is increased 3 TIMES the rate of reaction is increased by times .
Therefore order with respect to [A] =2
Rate =`k[A]^(2) [B]^(1)`


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