1.

For a reaction A+BtoProducts, rate law is -(d[A])/(dt)=k[A]_(0). The concentration of A left after time t when t=(1)/(k) is

Answer»

`([A]_(0))/(e)`
`[A]_(0)xxe`
`([A]_(0))/(e^(2))`
`(1)/([A]_(0))`

Solution :The GIVEN rate law SHOWS that it is a REACTION of 1st ORDER. For 1st order reacion, `[A] = [A]_(0) e^(-kt)`
When `t = (1)/(k), [A] = [A]_(0)e""^(-k(1)/(2))[A]_(0)e^(-1)=([A]_(0))/(e)`


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