1.

For a reaction A(g) hArr B(g) at equilibrium . The partial pressure of B is found to be one fourth ofthe partial pressure of A . The value of DeltaG^(@) of the reaction A rarrB is

Answer»

RT LN `4`
`-"RT" ln 4`
`"RT" log 4`
`-"RT" log 4`

SOLUTION :`A(g) hArrB(g) "" P_(B) = (1)/(4)P_(A) ""P_(A)=4P_(B)`
`K_(P) = (P_(6))/(P_(A)) = (P_(A)//4)/(P_(A)) = (1)/(4)`
At equilibrium , `DeltaG=O`.
`DeltaG^(@) =-RT l nK_(P) =- RTInK_(P) =- RTIn (1)/(4) = RT In 4`


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