For a reaction, A hArr P, the plots of [A[ and [P] with time at temperature T_(1) and T_2 are given ahead: . If T_(1) gt T_(1), the correct statement(s) is (are): (Assume DeltaH^(@) and DeltaS^(@) are independent of temperature and ratio of ln K at T_(1) to ln K at T_(2) as greater than (T_(2))/(T_(1)). Here, H,S,G and K are enthalpy, entropy, Gibbs energy and equilibrium constant, respectively.

For a reaction, A hArr P, the plots of [A[ and [P] with time at temper

1.	For a reaction, A hArr P, the plots of [A[ and [P] with time at temperature T_(1) and T_2 are given ahead: . If T_(1) gt T_(1), the correct statement(s) is (are): (Assume DeltaH^(@) and DeltaS^(@) are independent of temperature and ratio of ln K at T_(1) to ln K at T_(2) as greater than (T_(2))/(T_(1)). Here, H,S,G and K are enthalpy, entropy, Gibbs energy and equilibrium constant, respectively.
Answer» `DeltaH^(@) LT 0, DeltaS^(@) lt0` `DeltaG^(@) lt 0, DeltaH^(@) gt0` `DeltaG^(@) lt 0, DeltaS^(@) lt 0` `DeltaG^(@) lt 0, DeltaS^(@) gt 0` Solution :GIVEN that: `("ln "K_(1))/("ln "K_(2)) gt (T_(2))/(T_(1))""(Here" "T_(2)gtT_(1))` `T_(1)" ln "K_(1) gt T_(2)lnK_(2)` `RT_(1)lnK_(1)gtRT_(2)lnK_(2)`(It SHOWS that `DeltaG^(@)lt0)` `(-DeltaH^(@)-T_(1)DeltaS^(@))gt - (DeltaG^(@)-T_(2)DeltaS^(@))` `-DeltaH^(@)+T_(1)DeltaS^(@) gt -DeltaH^(@)+T_(2)DeltaS^(@)` Above expression will be correct ONY when `(DeltaH^(@) lt 0)` `T_(1)DeltaS^(@) gt T_(2)DeltaS^(@)` Given that `T_(2) gt T_(1)` `thereforeDeltaS^(@) lt0`