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For a reaction A → P, the rate of the reaction doubles when the concentration of A is increased by two times.1. Determine the order of the reaction.2. Derive an expression to determine the 14th life period of above order reaction. |
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Answer» 1. First order reaction. 2. 1/4th life of a first order reaction can be determined as follows. \(k=\frac{2.303}{t}log\frac{[R]_0}{[R]}\) When t = t/4, [R] can be taken as \(\frac{[R]_0}{4}\) \(k=\frac{2.303}{t/4}log\,4\,;\) \(k=\frac{2.303}{t/4}\times log\,4\) tt/4 = \(\frac{2.303\,\times\,log\,4}{k}\) \(=\frac{2.303\,\times\,0.6020}{k}\) \(=\frac{1.386}{k}\) |
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