1.

For a reaction A → P, the rate of the reaction doubles when the concentration of A is increased by two times.1. Determine the order of the reaction.2. Derive an expression to determine the 14th life period of above order reaction.

Answer»

1. First order reaction.

2. 1/4th life of a first order reaction can be determined as follows.

\(k=\frac{2.303}{t}log\frac{[R]_0}{[R]}\)

When t = t/4, [R] can be taken as \(\frac{[R]_0}{4}\)

\(k=\frac{2.303}{t/4}log\,4\,;\)

\(k=\frac{2.303}{t/4}\times log\,4\)

tt/4\(\frac{2.303\,\times\,log\,4}{k}\)

\(=\frac{2.303\,\times\,0.6020}{k}\) 

\(=\frac{1.386}{k}\)



Discussion

No Comment Found

Related InterviewSolutions