1.

For a reaction at 25^(@)C, enthalpy and entropy changes are -11.7xx10^(3)" J "mol^(-1) and -105" J "mol^(-1)K^(-1) respectively. What is the Gibb's free energy?

Answer»

15.05 kJ
19.59 kJ
2.55 kJ
22.55 kJ

Solution :`T=25+273=298K`,
`DeltaG=DeltaH-TDeltaS=-11.7xx10^(3)-298xx(-105)`
`=19590J=19.59kJ`


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