For a reaction at `25^(@)C` enthalpy change `(DeltaH)` and entropy change `(DeltsS)` are `-11.7 K J mol^(-1)` and `-105J mol^(-1) K^(-1)`, respectively. Find out whther this reaction is spontaneous or not?

For a reaction at `25^(@)C` enthalpy change `(DeltaH)` and entropy cha

1.	For a reaction at `25^(@)C` enthalpy change `(DeltaH)` and entropy change `(DeltsS)` are `-11.7 K J mol^(-1)` and `-105J mol^(-1) K^(-1)`, respectively. Find out whther this reaction is spontaneous or not?
Answer» Given, `DeltaH = - 11.7 xx 10^(3) J mol^(-1)` `DeltaS =- 105 J mol^(-1) K^(-1), T = 298 K` `DeltaG = DeltaH -T DeltaS =- 11700 - 298 xx (-105)` `= 19590J =+ 19.59kJ` Since `DeltaG = +ve` Therefore, reaction is not spontaneous.

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For a reaction at `25^(@)C` enthalpy change `(DeltaH)` and entropy change `(DeltsS)` are `-11.7 K J mol^(-1)` and `-105J mol^(-1) K^(-1)`, respectively. Find out whther this reaction is spontaneous or not?

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