1.

For a reaction at equilibrium, the partial pressure of B is found to be one fourth of the partial pressure of A. The value of Delta G^(theta) of the reaction A rarr B is

Answer»

`-RT log 4`
`2.303 RT log 4`
`-2.303 RT log1/ 4`
`2.303 R log 4`

Solution :`K = (1)/(4)`
:. `Delta G = - 2.303 RT log. (1)/(4)`
`= 2.303 RT log 4`


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