1.

For a reaction Ato products, the graph drawn between rate of reaction Vs (a-x) gives a straight line with the slope 0.0693 "min"^(-1).Initial concentration of the reactant is 0.4M . After 20 minutes the rate of reaction is calculated as 6.93xx10^(-x). Report the value of x?

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Solution :`r=K.(a-x)^(N)impliesn=1,r=K(a-x),0.0693xx20=2.303xx"log"(0.4/(Ct))`
`2xx0.3010=log(0.4/(Ct)),4=0.4/(C_(t))impliesC_(t)=0.1,r=K.(C_(t))^(1)=0.693xx(0.1)^(1)=6.93xx10^(-3)`


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