1.

For a reaction `Br_(2)(l)+Cl_(2)(g)to2BrCl` at `300K` the value of `DeltaH=7kcal` and `DeltaS` is `25 cal K^(-1)`. The free energy change isA. `-500 cal`B. `7493 cal`C. `18 kJ`D. `150 kcal`

Answer» Correct Answer - A
Apply `DeltaG=DeltaH-T DeltaS`
`=7000 cal-300xx25=-500cal`


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