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For a reaction `DeltaH=+29kJ" "mol^(-1),DeltaS=-35KJ^(-1)" "mol^(-1)` at what temperature, the reaction will be spontaneous?A. `828.7^(@)C`B. `828.7K`C. Spontaneous at all temperatureD. non possible |
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Answer» Correct Answer - D `DeltaG=DeltaH-TDeltaS` When `DeltaH=+ve,DeltaS=-ve` then `DeltaG` will be positive and the reaction is non-spontaneous. |
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