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For a reaction DeltaH=(+3kJ), DeltaS=(+10J//K)beyond which temperature this reaction will be spontaneous |
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Answer» 300 K For the SPONTANEOUS REACTION the `DeltaG` MUST be NEGATIVE. `DeltaH=3kJ=+3000 J` `DeltaS=+10 J//K` If `T=300 K implies DeltaG=3000-300xx10=0` If `T=200 K implies DeltaG=3000-200xx10=1000 J` If `T=273 K implies DeltaG=3000-273xx10=270 J` If T = 373 K `DeltaG=3000-373xx10=-730 J` Hence, beyond 373 temperature the reaction will be spontaneous. |
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