1.

For a reaction having rate law expression : Rate = k[A]^(3//2) [B]^(-1//2) If the concentration of both A and B become four times the rate of reaction

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become FOUR times
becomes 16 times
DECREASES four times
reamains same .

Solution :(A) `r_(1)=k (a)^(3//2)(b)^(-1//2)`
`r_(2) = k (4a)^(3//2)(4b)^(-1//2)`
`(r_(2))/(r_(1))=(4)^(3//2)(4)^(-1//2)=4 ` .


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