1.

For a reaction Rate = "k [acetone]"^((3)/(2)) then unit of rate constant and rate of reaction respectively is

Answer»

`("mol "L^(-1)s^(-1)), ("mol"^(-1//2)L^(1//2)s^(-1))`
`("mol"^(-1//2)L^(1//2)s^(-1)), ("mol "L^(-1)s^(-1))`
`("mol"^(1//2)L^(1//2)s^(-1)), ("mol "L^(-1)s^(-1))`
`("mol "LS^(-1)), ("mol"^(1//2)L^(1//2)s)`

Solution :Rate `=K[A]^(n)`
Rate `=(-d[A])/(DT), " unit of rate"=("mol "L^(-1))/(s)="mol "L^(-1)s^(-1)`
unit of rate constant `=(("mol "L^(-1)s^(-1)))/(("mol "L^(-1))^(n))="mol"^(1-n)L^(n-1)s^(-1)`
In this CASE, rate `=k["Acetone"]^(3//2)`
`n=3//2`
`"mol"^(1-(3//2))L^((3//2)-1)s^(-1) rArr "mol"^(-(1//2))L^((1//2))s^(-1)`


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