For a reaction the free energy change, DeltaG=-RT ln K_(p)+RTlnQ_(p) w – InterviewSolution

1.	For a reaction the free energy change, DeltaG=-RT ln K_(p)+RTlnQ_(p) where K_(P) = equilibrium constant, Q_(P)= reaction quotient. For the reaction to be in equilibrium state
Answer» `(Q_(p))/(K_(p))gt1` `(Q_(p))/(K_(p))LT1` `(Q_(p))/(K_(p))=1` `Q_(p)K_(p)=1` ANSWER :C

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