1.

For a reaction the graph drawn between t_(1//2) and a gives a straight line passing through the origin with the slope 2xx10^(2)"mole"^(-1) lit min. lf the initial concentation of the reactant is 1M, then the half life period is _______________X10^(2) min.

Answer»


Solution :`t_(1/2)=(C_(0))/(2xxK)impliest_(1/2)=(1/(2K))xxC_(0),t_(1/2)=(1xx4xx10^(2))/(2xx1),t_(1/2)=(4xx10^(2))/2=2xx10^(2)`


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