1.

For a reversible reaction at constant temperature and at constant pressure the equilibrium composition of reaction mixture corresponds to the lowest point on Gibbls energy Vs progress of reaction diagrams as shown. At equilibrium Gibbs energy of reaction is equal to zero. The value of `"log"_(10) K_(eq)` is equal to [`k_(eq)` is the equilibrium coustant]A. `- (Delta G^(@))/(RT)`B. `(T Delta S^(@) - Delta H^(@))/(2.303 RT)`C. `(Delta H^(@) - T Delta S^(@))/(RT)`D. `(RT)/(T Delta S^(@) - Delta H^(@))`

Answer» Correct Answer - B
`Delta G^(0) = Delta H^(0) - T Delta S^(0) = - 2.303 RT` log Keq


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