1.

For a reversible reaction : X_((g))+3Y_((g))hArr 2Z_((g)), Delta H=-40 kJ, the standard entropies of X,Y and Z are 60, 40 and 50 JK^(-1)mol^(-1) respectively. The temperature at which the above reaction attains equilibrium is about

Answer»

400 K
500 K
273 K
373 K

Solution :`X_((G))+3Y_((g))hArr 2Z_((g))`
`Delta S^(@)=2S^(@)(Z)-{S^(@)(X)+3S^(@)(Y)}`
`=2xx50-{60+3xx40}=100-180`
`=-80J K^(-1)MOL^(-1)`.
Given `Delta H^(@)=-40 kJ =-40,000 J`
`Delta G^(@)=Delta H^(@)-T Delta S^(@)`
At equilibrium, `Delta G^(@)=0`
`therefore Delta H^(@)=T Delta S^(@)`
or,`T=(Delta H^(@))/(Delta S^(@))=(40000)/(80)=500 K`.


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