1.

For a reversible reaction : X_((g))+3Y_((g))iff2Z_((g)), DeltaH=-40kJ the standard entropies of X, Y and Z are 60, 40 and 50 JK^(-1) mol^(-1) respectively. The temperature at which the above reaction attains equilibrium is about

Answer»

400 K
500 K
273 K
373 K

Solution : `X_((g))+3Y_((g))iff2Z_((g))`
`DeltaS^(@)=2S^(@)(Z)-{S^(@)(X)+3S^(@)(Y)}`
`=2xx50-{60+3xx40}=100-180 "= - 80 J K"^(-1) mol^(-1)`
`DeltaH^(@)=-40 kJ=-40,000 J,"" DeltaG^(@)=DeltaH^(@)-TDeltaS^(@)`
At equilibrium, `DeltaG^(@)=0 ""therefore DeltaH^(@)=TDeltaS^(@)`
`or, T = (DeltaH^(@))/(DeltaS^(@))=(40000)/(80)=500 K`.


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