1.

For a satellite moving in an orbit around the earth, the ratio of kinetic energy to potential energy is

Answer»

`1//2`
`1//sqrt(2)`
2
`sqrt(2)`

Solution :`-(GMM)/(R^(2))+momega^(2)R=0 RARR (GMm)/(R^(2))=momega^(2)R`
K.E. `=(1)/(2)I OMEGA^(2)=(1)/(2)m R^(2)omega^(2)=(GMm)/(2R)`
P.E. `=-(GMm)/(R )`
`:. K.E. =(|P.E.|)/(2):. (K.E.)/(|P.E.|)=(1)/(2)`


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