InterviewSolution
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InterviewSolution
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For a satellite moving in an orbit around the earth, ratio of kinetic energy to potential energy isA. 1B. `sqrt2`C. `(1)/(2)`D. `(1)/(sqrt2)` |
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Answer» Correct Answer - C For a satellite, moving in a circular orbit of radius r, orbital velocity `v_(0)=sqrt((GM)/(r ))` `therefore` Its `K.E. =(1)/(2)mv_(0)^(2)=(1)/(2)m(GM)/(r )=(1)/(2)(GMm)/(r )` and its `P.E.=(GMm)/(r )` (in magnitude) `therefore (K.E.)/(P.E.)=(GMm)/(2r)xx(r )/(GMm)=(1)/(2)` Note : We can directly use `P.E.=-2 (K.E.)` for a satellite. `therefore (K.E.)/(P.E.)=(1)/(2)` (in magnitude) |
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