1.

For a second order reaction, 2" A"toProducts, a plot of log t_(1//2) vs log a (where a is the initial concentration) will give an intercept equal to which of the following ?

Answer»

`1//k`
`LOG(1//2" k")`
`log (1//k)`
`log k`

SOLUTION :For a second ORDER reaction, `2A to ` PRODUCTS,
`k= (1)/(t)[(1)/([A])-(1)/([A]_(0))]`
When `t = t_(1//2), [A] = ([A]_(0))/(2)`
Hence, `t_(1//2) = (1)/(k)[(2)/([A]_(0))-(1)/([A]_(0))] = (1)/(k[A]_(0))`
`therefore log t_(1//2) = - log k - log [A]_(0) =- log k - log a`
Plot of log `t_(1//2)` vs log a will be linear with intercept = log k.


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