1.

For a second order reaction rate at a particular time is x . If the initial concentration is tripled , the rate will become :

Answer»

3X
`9X^(2)`
9x
27x

Solution :( C ) Rate = `k[A]^(2) = X `
If conc . Is tripled i.e A = [3A]
Rate = `k[3A]^(2) = k.9[A]=x `
`:. (x)/(x)=9` i.e BECOMES nine times (9x)


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