For a series L-C-R circuit with L=1.00 mH, C=10`muF` and `R=50Omega`, is driven with 5V AC voltage. At resosance, the current through the circuit isA. 0.2 AB. 0.25 AC. 0.15 AD. 0.1 A

For a series L-C-R circuit with L=1.00 mH, C=10`muF` and `R=50Omega`,

1.	For a series L-C-R circuit with L=1.00 mH, C=10`muF` and `R=50Omega`, is driven with 5V AC voltage. At resosance, the current through the circuit isA. 0.2 AB. 0.25 AC. 0.15 AD. 0.1 A
Answer» Correct Answer - D We know that for series L-C-R in circuit. `V_(rms) = sqrt(V_(R)^(2) + (V_(L)-V_(C)^(2)))` Given, `V_(L)`= 90V, `V_(C)` = 60V and `V_(R)` = 40 V Now, `V_(rms) = sqrt((40)^(2)+(90-60)^(2))`=50 V

Discussion

No Comment Found

Related InterviewSolutions

Can the phenomenon of resonance be exhibited in RL or RC circuit.
The impedance of a sereis `RL` circuit is same as the series `RC` circuit when connected to the same `AC` source separately keeping the same resistance. The frequency of the source isA. `(1)/(sqrt(LC))`B. `(1)/(2pi sqrt(LC))`C. `(R )/(L)`D. `(1)/(RC)`
The equation of an alternating voltage is `E = 220 sin (omega t + pi // 6)` and the equation of the current in the circuit is `I = 10 sin (omega t - pi // 6)`. Then the impedance of the circuit isA. 10 ohmB. 22 ohmC. 11 ohmD. 17 ohm
In an ac circuit, the current lags behind the voltage by `pi//3`. The components in the circuit areA. R and LB. R and CC. L and CD. Only R
In an ac circuit, the current lags behind the voltage by `pi//3`. The components in the circuit areA. R and LB. L and CC. R and CD. only R
A 200 km telephone wire has capacity of `0.014 muF km^(-1)`. If it carries an alternating current oif frequency 50kHz, what should be the value of an inductance required to be connected in series so that impedance is minimumn ?
In the circuit shown in figureure the `AC` source gives a voltage `V=20cos(2000t)`. Neglecting source resistance, the voltmeter and and ammeter readings will be .A. `0V,2.0A`B. `0V,1.4A`C. `5.6V,1.4A`D. `8V,2.0A`
A signal generator supplies a sine wave of `200V, 5kHz` to the circuit shown in the figureure. Then, choose the wrong statement. .A. The current in te resistive brance is `0.2 A`B. the current in the capacitive branch is `0.126 A`C. Total line current is `~~0.283A`D. Current in both the branches is same
In an `AC` circuit, the applied potential difference and the current flowing are given by `V=20sin100tvolt,I=5sin(100t-pi/2)` amp The power consumption is equal toA. `1000W`B. `40W`C. `20W`D. zero
In an `AC` circuit, the current is given by `i=5sin(100t-(pi)/2)` and the `AC` potential is `V=200sin(100t)`volt. Then the power consumption isA. `20` wattsB. `40` wattC. `1000` wattD. `0` watt

For a series L-C-R circuit with L=1.00 mH, C=10`muF` and `R=50Omega`, is driven with 5V AC voltage. At resosance, the current through the circuit isA. 0.2 AB. 0.25 AC. 0.15 AD. 0.1 A

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment