Saved Bookmarks
| 1. |
For a short magnetic dipole of magnetic moment 0.5 Am^(2). Find the magnetic field at a point ( a) 1 m on the axis and from the cetre of the magnet ( dipole ) ( b) 1 m on the equatorial line from the centre ( c) at an angle of 60^(@) w.r. to the line joining the point and the centre of the dipole at distance 1 m. |
Answer» SOLUTION :We know that ,  (a) `"" B_(A)=((mu_(o))/(4pi))(2m)/(R^(3))`tesla = `(10^(-7)xx2xx0.5)/(1^(3))` `= 1.0 xx10^(-7)`T (b) `"" B_(B)=((mu_(o))/(4pi))(m)/(r^(3))`tesla = `(10^(-7)xx0.5)/(1^(3)) = 0.5 xx10^(-7)`T (C)`"" B = (mu_(o))/(4pi)(m)/(r^(3))sqrt(3cos^(2)theta+1)=(10^(-7)xx0.5)/(1^(3))sqrt(3cos^(2)60^(@)+1)` `B = (0.5xx10^(-7)xx1.732)/(4) = 0.2165 xx 10^(-7) T ~~ 0.22 xx 10^(7) `T |
|