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For a spontaneous reaction, `DeltaG,` equilibrium constant (K) and `E_(cell)^(@)` will be respectively:A. `-ve`, `gt 1`, `+ve`B. `+ve`, `gt 1`, `-ve`C. `-ve`, `lt 1`, `-ve`D. `-ve`, `gt 1`, `-ve` |
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Answer» Correct Answer - A For a spontaneous reaction `DeltaG` is `-ve` `DeltaG=-RT ln K` or `ln K` is `+ve implies K gt1` Now `DeltaG=-nFE_("cell")` As `DeltaG` is `-ve` for a spontaneous reaction. `E_("cell")` for such a reaction is `+ve`. |
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