For a symmetrical distribution, which is correct ?A) Mean > Median > M

1.	For a symmetrical distribution, which is correct ?A) Mean > Median > ModeB) Mean < Median < ModeC) Mean = Median = ModeD) \(\frac{Mean\,+\,Median}{2}\) = Mode
Answer» Correct option is: C) Mean = Median = Mode For a symmetrical distribution, we have Mean = Median = Mode Correct option is: C) Mean = Median = Mode

For a symmetrical distribution, which is correct ?A) Mean > Median > ModeB) Mean < Median < ModeC) Mean = Median = ModeD) \(\frac{Mean\,+\,Median}{2}\) = Mode

Answer»

Correct option is: C) Mean = Median = Mode

For a symmetrical distribution, we have

Mean = Median = Mode

Correct option is: C) Mean = Median = Mode

Discussion

No Comment Found

Related InterviewSolutions

The mean expenditure of a person from Monday to Wednesday is Rs.250, and the mean expenditure from Wednesday to Friday is Rs. 400. If he spend Rs. 300 on Wednesday, find the mean expenditure of the person from Monday to Friday.
Coefficients of variation of two distribution are 15 and 20 and their means are 20 and 10 respectively. If their standard deviations are `sigma_1` and `sigma_2` thenA. `3sigma_1=2sigma_2`B. `sigma_1 lt sigma_2`C. `2sigma_1 =3sigma_2`D. None of these
Given the variance of 30 observations is 20. if each of the observations is divided by 2, then new variance of the resulting oservations isA. 20B. 10C. 5D. None of these
Mode is A. least frequent value B. middle most value C. most frequent value D. None of these
Given the that variance of 50 observations is 18. If each of the 50 observations is increased by 2, then variance of new data isA. 50B. 52C. 48D. 25
The following table shows the ages of the patients admitted in a hospital during a year:Find the mode and the mean of the data given above. Compare and interpret the two measures of central tendency.
Calculate the missing frequency form the following distribution, it being given that the median of the distribution is 24. Age in years: 0 - 10 10 - 20 20 - 30 30 - 40 40 - 50 No. of persons: 5 25 ? 18 7
Find the missing frequencies and the median for the following distribution if the mean is 1.46. No. of accidents:012345 Total Frequency (No. of days):46??25105200
When a dice is thrown, the total number of posible outcomes is ________.A. 6B. 1C. 3D. 4
If a dics is thrown, then the probability of getting an even number is _______.

For a symmetrical distribution, which is correct ?A) Mean &gt; Median &gt; ModeB) Mean &lt; Median &lt; ModeC) Mean = Median = ModeD) \(\frac{Mean\,+\,Median}{2}\) = Mode

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment

For a symmetrical distribution, which is correct ?A) Mean > Median > ModeB) Mean < Median < ModeC) Mean = Median = ModeD) \(\frac{Mean\,+\,Median}{2}\) = Mode