1.

For a transistor beta= 40 and I_B = 25 muAI_B = 25 mu A. Find the value of l_E .

Answer»

SOLUTION :`beta = ((Delta I_C )/( Delta I_B ))_(V_(CE))`
(If only d.c. values are considered)
` thereforeI_C= betaI_B= 40 xx 25 xx 10^(-6)=1000 xx 10^(-6) A `
` thereforeI_E= I_B+I_C `
` =( 25xx 10^(-6)+ 1000 xx 10^(-6) ) AMP `
` = 1025mu A= 1.025mA `


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