For a transistor the current amplification factor is 0.8 . If the transistor is now in common emitter configuration , the change in collector current when the base current changes by 6 mA is :

For a transistor the current amplification factor is 0.8 . If the tran

1.	For a transistor the current amplification factor is 0.8 . If the transistor is now in common emitter configuration , the change in collector current when the base current changes by 6 mA is :
Answer» 6 mA 4.8 mA 24 mA 8 mA Solution :As `ALPHA= 0.8 and BETA = alpha/(1-alpha) =(0.8)/(1-0.8)=4` `(DeltaI_c)/(DeltaI_b) = 4 " or "DeltaI_c=4xx6 mA = 24 mA`

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For a transistor the current amplification factor is 0.8 . If the transistor is now in common emitter configuration , the change in collector current when the base current changes by 6 mA is :

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